By M. Sharma
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The analysis of variance tells us that there is no difference in the treatments. There is no need to proceed with Fisher’s LSD method to decide which mean is difference. (c) Analyze the residuals from this experiment. Are the analysis of variance assumptions satisfied? There is nothing unusual about the residual plots. Normal plot of residuals Residuals vs. 3. Does this graph adequately summarize the results of the analysis of variance in part (b). Yes. 3-16 Solutions from Montgomery, D. C. 8 M e a n D e n s ity 3-11 Rework Part (d) of Problem 3-10 using the Tukey method.
C. 0002 (b) Use Tukey’s test to compare pairs of treatment means. 01. 04 S yi . 266 1 vs. 266 1 vs. 266 2 vs. 266 1 and 2 are different. 2 and 3 are different. Notice that the results indicate that the mean of treatment 2 differs from the means of both treatments 1 and 3, and that the means for treatments 1 and 3 are the same. Notice also that the Fisher LSD procedure (see the computer output) gives the same results. 3 to compare the treatment means. What conclusions can you draw? How do they compare with the conclusions from part (a).
B) Explain the difference between the Tukey and Fisher procedures. Both Tukey and Fisher utilize a single critical value; however, Tukey’s is based on the studentized range statistic while Fisher’s is based on t distribution. 3-3 Reconsider the experiment in Problem 3-1. Find a 95 percent confidence interval on the mean tensile strength of the portland cement produced by each of the four mixing techniques. Also find a 95 3-4 Solutions from Montgomery, D. C. (2004) Design and Analysis of Experiments, Wiley, NY percent confidence interval on the difference in means for techniques 1 and 3.
Build Your Own Test Instruments by M. Sharma