By E. Russell Johnston Jr., Elliot R. Eisenberg, Ferdinand Pierre Beer, David F. Mazurek, Phillip J. Cornwell

ISBN-10: 0073529400

ISBN-13: 9780073529400

Carrying on with within the spirit of its profitable earlier versions, the 9th version of Beer, Johnston, Mazurek, and Cornwell's Vector Mechanics for Engineers presents conceptually actual and thorough insurance including an important refreshment of the workout units and on-line supply of homework difficulties on your scholars. approximately 40 percentage of the issues within the textual content are replaced from the former edition.

The Beer/Johnston textbooks brought major pedagogical strategies into engineering mechanics educating. The constant, actual problem-solving technique offers your scholars the simplest chance to profit statics and dynamics. while, the cautious presentation of content material, unequalled degrees of accuracy, and a focus to element have made those texts the traditional for excellence.

This textual content is a mix of the 9th versions of Vector Mechanics for Engineers: Statics and Vector Mechanics for Engineers: Dynamics.

**Read or Download Vector Mechanics for Engineers: Statics and Dynamics (9th Edition) PDF**

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**Additional resources for Vector Mechanics for Engineers: Statics and Dynamics (9th Edition)**

**Sample text**

Thus, using Eqs. 11), we write 1 slug 5 1 lb ? 59 N ? 3048 m/s2 and, recalling Eq. 5), 1 slug 5 1 lb ? S. customary units (pounds). S. customary unit into SI units, one simply multiplies or divides by the appropriate conversion factors. For example, to convert the moment of a force which was found to be M 5 47 lb ? in. 11) and write M 5 47 lb ? in. 4 mm) 5 5310 N ? 31 N ? S. customary units. For example, if the moment of a force was found to be M 5 40 N ? m, we write, following the procedure used in the last paragraph of Sec.

Two cases may be encountered, depending upon the way in which each of the given forces is defined: Case 1. The force F is defined by its magnitude F and the angle a it forms with the x axis. The x and y components of the force can be obtained by multiplying F by cos a and sin a, respectively [Example 1]. Case 2. The force F is defined by its magnitude F and the coordinates of two points A and B on its line of action (Fig. 23). The angle a that F forms with the x axis may first be determined by trigonometry.

The vectors representing the forces acting on A may be added by the polygon rule (Fig. 14b). 6 Resolution of a Force into Components Q P P S A Q S R A (a) (b) Fig. 14 Q the particle A as the given forces. As indicated above, the order in which the vectors P, Q, and S representing the given forces are added together is immaterial. 6 F Q A F P P Q F A P (c) Fig. 15 Q 1. One of the Two Components, P, Is Known. The second com- ponent, Q, is obtained by applying the triangle rule and joining the tip of P to the tip of F (Fig.

### Vector Mechanics for Engineers: Statics and Dynamics (9th Edition) by E. Russell Johnston Jr., Elliot R. Eisenberg, Ferdinand Pierre Beer, David F. Mazurek, Phillip J. Cornwell

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